A resting car starts accelerating uniformly at #a_1# rate a then moves at a constant velocity =4m/s then decelerates at a constant rate #a_2#. the velocity of the car is greater than 2m/s for 10sec. What is the distance traversed by the car?
1 Answer
The total distance was
Explanation:
The car accelerates uniformly from rest to
I will assume we need to find distance from start until the deceleration brings the car to a stop.
We are also told that the velocity was greater than
Because both
#v_"ave" = (u + v)/2
Therefore the total distance was
I hope this helps,
Steve