A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $16$ $16$ , $2$ $2$ , and $4$ $4$ , respectively. What is the rectangle's area?

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A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $16$ $16$ , $2$ $2$ , and $4$ $4$ , respectively. What is the rectangle's area?

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Answer 1 · 2017-12-29T21:00:19

$\approx 63.5 square units$ $~~63.5" square units"$

Explanation:

$the area of the rectangle = 4 B$ $"the area of the rectangle "=4B$

$to find B use Pythagoras' theorem$ $"to find B use "color(blue)"Pythagoras' theorem"$

$\Rightarrow B = \sqrt{16^{2} - 2^{2}} = \sqrt{252} = 6 \sqrt{7}$ $rArrB=sqrt(16^2-2^2)=sqrt(252)=6sqrt7$

$\Rightarrow area of rectangle = 4 \times 6 \sqrt{7} \approx 63.5 to 1 dec. place$ $rArr"area of rectangle "=4xx6sqrt7~~63.5" to 1 dec. place"$

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A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $16$ $16$ , $2$ $2$ , and $4$ $4$ , respectively. What is the rectangle's area?

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Explanation:

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A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of 16 1616 , 2 22 , and 4 44 , respectively. What is the rectangle's area?

1 Answer

Explanation:

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Impact of this question

A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $16$ $16$ , $2$ $2$ , and $4$ $4$ , respectively. What is the rectangle's area?