A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $9$ , $5$ , and $22$ , respectively. What is the rectangle's area?

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Answer 1 · 2016-06-30T00:56:14

$22*sqrt56~~164.6squnit$

Given
$A->"Hypotenuse"=9$
$C->"Other side "=5$

Applying Pythagorus theorem

$B=sqrt(A^2-C^2)=sqrt(9^2-5^2)$
$=>B=sqrt56$

The side of the rectangle adjacent to side B is 22.

So area of the rectangle
$=sqrt56xx22~~164.6squnit$

A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of 9 9 , 5 5 , and 22 22 , respectively. What is the rectangle's area?