A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $6$ $6$ , $4$ $4$ , and $9$ $9$ , respectively. What is the rectangle's area?

Question

1745 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-01T14:07:22

The reqd. Area of rectangle $= 18 \sqrt{5} ≅ 40.248$ $=18sqrt5~=40.248$ sq.unit..

In the given right triangle with hypo.=A, we have, by Pythagoras Theorem, $B^2+C^2=A^2..........(1)$ .

$A=6, C=4$ ...[Given] & $(1) rArr B^2=36-16=20 rArr B=sqrt20=2sqrt5.$

Hence, the reqd. Area of rectangle $=B xx$ length of side adjacent to $B$ $=2sqrt5*9=18sqrt5~=18*2.236~=40.248$ sq.unit.

A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of 6 66 , 4 44 , and 9 99 , respectively. What is the rectangle's area?