A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $7/8$ , $3/5$ , and $4$ , respectively. What is the rectangle's area?

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Answer 1 · 2016-05-15T06:56:04

Rectangle's area is $1.803$

As side A is hypotenuse and has length $7/8$ and C has length $3/4$ , using Pythagoras theorem

Length of side B is $sqrt((7/8)^2-(3/4)^2)$

= $sqrt(49/64-9/16)=sqrt(49/64-36/64)=sqrt(13)/8$

Now one side of rectangle is $4$ and side B is $sqrt(13)/8$

Hence its area is $sqrt(13)/8xx4=sqrt13/2=1.803$

A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of 7/8 7/8 , 3/5 3/5 , and 4 4 , respectively. What is the rectangle's area?