A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $9$ $9$ , $6$ $6$ , and $9$ $9$ , respectively. What is the rectangle's area?

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A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $9$ $9$ , $6$ $6$ , and $9$ $9$ , respectively. What is the rectangle's area?

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Answer 1 · 2017-11-19T12:53:34

Area of rectangle $= 27 \sqrt{5} = 60.3638$ $=27sqrt5 = 60.3638$

Explanation:

$A^{2} = B^{2} + C^{2}$ $A^2 = B^2 + C^2$
$9^{2} = B^{2} + 6^{2}$ $9^2 = B^2 + 6^2$
$B = \sqrt{9^{2} - 6^{2}} = \sqrt{45} = 3 \sqrt{5}$ $B = sqrt(9^2-6^2) = sqrt(45) = 3sqrt5$
Length of rectangle is 9 and breadth is $3 \sqrt{5}$ $3sqrt5$

Area of rectangle $= l \cdot b = 9 \cdot 3 \sqrt{5}$ $= l * b =9 * 3sqrt5$

= $27 \sqrt{5} = 60.3638$ $27 sqrt5 = 60.3638$

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A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $9$ $9$ , $6$ $6$ , and $9$ $9$ , respectively. What is the rectangle's area?

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Explanation:

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A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $9$ $9$ , $6$ $6$ , and $9$ $9$ , respectively. What is the rectangle's area?