A rocket travelling at +88m/s is accelerated to +132m/s over a 15s interval. What is its displacement during this time?

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Answer 1 · 2018-04-08T12:10:37

The displacement is #=1650m#

Apply the equation of motion

#v=u+at#

#a=(v-u)/t=(132-88)/15=2.93ms^-2#

The displacement is calculated with the equation

#v^2=u^2+2as#

The displacement is

#s=(v^2-u^2)/(2a)=(132^2-88^2)/(2*2.93)=1650m#