A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?

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A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?

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Answer 1 · 2017-03-08T06:46:47

The combined gas law holds that $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1=(P_2V_2)/T_2$ . The amount of gas is assumed to be constant.

Explanation:

And so $P_{2} = \frac{P_{1} V_{1} T_{2}}{T_{1} V_{2}} .$ $P_2=(P_1V_1T_2)/(T_1V_2).$

The RHS expression clearly has the units of pressure as required, why?

$P_2=(1.13*atmxx2.25*cancelLxx302*cancelK)/(286*cancelKxx1.89*cancelL)=??atm$

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A sample of an gas has a volume of 2.25 L at 286 K and 1.13 atm. What is the pressure when the volume is 1.89 L and temperature is 302 K?

1 Answer

Explanation:

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