A sample of an ideal gas has a volume of 2.28 L at 289 K and 1.01 atm. What is the pressure when the volume is 1.65 L and the temperature is 305 K?

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A sample of an ideal gas has a volume of 2.28 L at 289 K and 1.01 atm. What is the pressure when the volume is 1.65 L and the temperature is 305 K?

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Answer 1 · 2018-08-05T10:45:08

Well, I make $P_{2} ≅ 1.4 \cdot a t m$ $P_2~=1.4*atm$

Explanation:

From the old combined gas equation for a GIVEN quantity of gas.....

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1=(P_2V_2)/T_2$ ...

And so $P_{2} = \frac{P_{1} V_{1}}{T_{1}} \times \frac{T_{2}}{V_{2}}$ $P_2=(P_1V_1)/T_1xxT_2/V_2$

$= \frac{1.01 \cdot a t m \times 2.28 \cdot L}{289 \cdot K} \times \frac{305 \cdot K}{1.65 \cdot L} = ? ? \cdot a t m$ $=(1.01*atmxx2.28*L)/(289*K)xx(305*K)/(1.65*L)=??*atm$

Is the increase in pressure CONSISTENT with an increase in temperature, and a DECREASE in volume? Si or non....?

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A sample of an ideal gas has a volume of 2.28 L at 289 K and 1.01 atm. What is the pressure when the volume is 1.65 L and the temperature is 305 K?

1 Answer

Explanation:

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