Question

A sample of an ideal gas has a volume of 2.34 L at 279 K and 1.10 atm. What is the pressure when the volume is 1.78 L and the temperature is 304 K?

Answer 1

Pressure = `1.6 atm`

Explanation:

Use the formula `(P_1V_1)/T_1 = (P_2V_2)/T_2`, where `P_1` is the initial pressure, `V_1` is the initial volume, and `T_1` is the initial temperature. And `V_2\, P_2\, T_2` are the final values (with the variable you're trying to find!)

Substitute the values into the formula.

`((1.10atm)(2.34L))/(279K)= ((P_2)(1.78L))/(304K)`

`(304)(1.10)(2.34) = (P_2)(1.78)(279)`

`782.5 = 496.6 (P_2)`

`P_2 = 1.6 atm`