A sample of an ideal gas has a volume of 2.34 L at 279 K and 1.10 atm. What is the pressure when the volume is 1.78 L and the temperature is 304 K?

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A sample of an ideal gas has a volume of 2.34 L at 279 K and 1.10 atm. What is the pressure when the volume is 1.78 L and the temperature is 304 K?

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Answer 1 · 2016-05-08T03:24:06

Pressure = $1.6 a t m$ $1.6 atm$

Explanation:

Use the formula $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1 = (P_2V_2)/T_2$ , where $P_{1}$ $P_1$ is the initial pressure, $V_{1}$ $V_1$ is the initial volume, and $T_{1}$ $T_1$ is the initial temperature. And $V_{2}, P_{2}, T_{2}$ $V_2\, P_2\, T_2$ are the final values (with the variable you're trying to find!)

Substitute the values into the formula.

$\frac{(1.10 a t m) (2.34 L)}{279 K} = \frac{(P_{2}) (1.78 L)}{304 K}$ $((1.10atm)(2.34L))/(279K)= ((P_2)(1.78L))/(304K)$

$(304) (1.10) (2.34) = (P_{2}) (1.78) (279)$ $(304)(1.10)(2.34) = (P_2)(1.78)(279)$

$782.5 = 496.6 (P_{2})$ $782.5 = 496.6 (P_2)$

$P_{2} = 1.6 a t m$ $P_2 = 1.6 atm$

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A sample of an ideal gas has a volume of 2.34 L at 279 K and 1.10 atm. What is the pressure when the volume is 1.78 L and the temperature is 304 K?

1 Answer

Explanation:

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