A sample of compressed methane has a volume of 648 mL at a pressure of 503 kPa. To what pressure would the methane have to be compressed in order to have a volume of 216 mL?

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A sample of compressed methane has a volume of 648 mL at a pressure of 503 kPa. To what pressure would the methane have to be compressed in order to have a volume of 216 mL?

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Answer 1 · 2017-03-14T08:59:17

The pressure is $= 1509 k P a$ $=1509kPa$

Explanation:

We apply Boyle's Law

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

$P_{1} = 503 k P a$ $P_1=503kPa$

$V_{1} = 648 m L$ $V_1=648mL$

$V_{2} = 216 m L$ $V_2=216mL$

$P_{2} = \frac{V_{1}}{V_{2}} \cdot P_{1}$ $P_2=V_1/V_2*P_1$

$= \frac{648}{216} \cdot 503 = 1509 k P a$ $=648/216*503=1509kPa$

Answer 2 · 2017-03-14T09:01:02

Well, Boyle's law holds that $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ ............

Explanation:

So we solve for $P_{2} = \frac{P_{1} V_{1}}{V_{2}} = \frac{503 \cdot k P a \times 648 \cdot m L}{216 \cdot m L} = ? ? \cdot k P a$ $P_2=(P_1V_1)/V_2=(503*kPaxx648*mL)/(216*mL)=??*kPa$ .

Clearly, the pressure increases, here almost threefold.

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A sample of compressed methane has a volume of 648 mL at a pressure of 503 kPa. To what pressure would the methane have to be compressed in order to have a volume of 216 mL?

2 Answers

Explanation:

Explanation:

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