A sample of gas at a pressure of 121.59 kPa, a volume of 31 L, and a temperature of 360 K contains how many moles of gas?

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Answer 1 · 2016-09-17T07:56:23

The sample of gas contains 1.3 moles of gas.

Use the ideal gas law as shown below.

#P="121.59 kPa"#
#V="31 L"#
#T="360 K"#
#R=8.3144598 "L kPa K"^(-1) "mol"^(-1)"#

Rearrange the equation to isolate #n#, plug in the known values, and solve.

#n=(PV)/(RT)#

#n=(121.59cancel"kPa"xx31cancel"L")/(8.3144598cancel"L kPa K"^(-1) "mol"^(-1)xx360cancel"K")="1.3 mol"# (rounded to two significant figures)