A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume?

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A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume?

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Answer 1 · 2016-03-11T05:24:33

The volume of the gas is 73.1 L.

Explanation:

This question requires the ideal gas law. The equation for the ideal gas law is $P V = n R T$ $PV=nRT$ , where $P$ $P$ is pressure, $V$ $V$ is volume, $n$ $n$ is moles, $R$ $R$ is the gas constant, and $T$ $T$ is the temperature in Kelvins.

Given/Known
$P = 1.09 atm$ $P="1.09 atm"$
$n = 3.66 moles gas$ $n="3.66 moles gas"$
$R = 0.082057338 \frac{L\cdotatm}{K\cdotmol}$ $R=0.082057338("L·atm")/("K·mol")$
https://en.m.wikipedia.org/wiki/Gas_constant
$T = 265 K$ $T="265 K"$

Unknown
$V$ $V$

Solution
Rearrange the equation to isolate volume. Substitute the known values into the equation and solve.

$P V = n R T$ $PV=nRT$

$V = \frac{n R T}{P}$ $V=(nRT)/P$

$V=(3.66cancel"mol"·0.082057338("L"·cancel("atm"))/(cancel("K")·cancel("mol"))·265cancel"K")/(1.09cancel"atm")="73.1 L of gas"$ rounded to three significant figures

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A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume?

1 Answer

Explanation:

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