A saturated solution of $P b B r_{2}$ $PbBr_2$ is prepared by dissolving the solid salt in water. The concentration of $P b_{2}^{+}$ $Pb_2^+$ in solution is found to be 0.0115 M. What is the Ksp for $P b B r_{2}$ $PbBr_2$ ?

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A saturated solution of $P b B r_{2}$ $PbBr_2$ is prepared by dissolving the solid salt in water. The concentration of $P b_{2}^{+}$ $Pb_2^+$ in solution is found to be 0.0115 M. What is the Ksp for $P b B r_{2}$ $PbBr_2$ ?

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Answer 1 · 2017-07-14T19:01:37

$K_{s p} = 6.1 \times 10^{- 6}$ $K_(sp)=6.1xx10^-6$

Explanation:

We interrogate the solubility equilibrium.........

$P b B r_{2} (s) ⇌ P b^{2 +} + 2 B r^{-}$ $PbBr_2(s) rightleftharpoonsPb^(2+) + 2Br^(-)$

Now $K_{s p} = [P b^{2 +}] [B r^{-}]$ $K_(sp)=[Pb^(2+)][Br^-]$ .........And if we say that the solubility of $P b B r_{2} \equiv S$ $PbBr_2-=S$ , then by stoichiometry........

$K_{s p} = [S] {[2 S]}^{2} = 4 S^{3}$ $K_(sp)=[S][2S]^2=4S^3$ (because $S = [P b^{2 +}]$ $S=[Pb^(2+)]$ , and $[B r^{-}] = 2 S$ $[Br^-]=2S$

$= 4 \times {(0.0115)}^{3} = 6.1 \times 10^{- 6}$ $=4xx(0.0115)^3=6.1xx10^-6$ .........

Can you define what is meant by a $saturated solution......?$ $"saturated solution......?"$

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A saturated solution of $P b B r_{2}$ $PbBr_2$ is prepared by dissolving the solid salt in water. The concentration of $P b_{2}^{+}$ $Pb_2^+$ in solution is found to be 0.0115 M. What is the Ksp for $P b B r_{2}$ $PbBr_2$ ?

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A saturated solution of PbBr2PbBr_2 is prepared by dissolving the solid salt in water. The concentration of Pb+2Pb_2^+ in solution is found to be 0.0115 M. What is the Ksp for PbBr2PbBr_2?

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A saturated solution of $P b B r_{2}$ $PbBr_2$ is prepared by dissolving the solid salt in water. The concentration of $P b_{2}^{+}$ $Pb_2^+$ in solution is found to be 0.0115 M. What is the Ksp for $P b B r_{2}$ $PbBr_2$ ?