A shell is ﬁred from the ground with an initial speed of #1.70 x 10^3# m/s at an initial angle of 55.0° to the horizontal, Neglecting air resistance, what is the shell's horizontal range and the amount of time the shell is in motion?

Question

43403 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-13T14:06:46

#(a)# #277.1"km"#

#(b)# # 284.2"s"#

#(a)# The range, assuming level ground, is given by:

#d=(v^2)/(g)sin(2theta)#

#:.d=((1.7xx10^(3))^(2)xx0.9397)/(9.8)#

#d=0.2771xx10^(6)"m"#

#d=277.1"km"#

#(b)#

The horizontal component of velocity is constant and is equal to #vcostheta#.

So #t=s/v=(0.2771xx10^(6))/(1.7xx10^(3)xxcos55)#

#:.t=(277.1)/(1.7xx0.573)#

#t=284.2"s"#