A #sigma# bond is the same thing as a single bond. So what is a #pi# bond?

1 Answer
Nov 28, 2017

Here's the answer...

Explanation:

#color(red)(sigma) "bonds"# are the formed by the overlapping of the #(s-p)# or, #(s-s)# orbitals by head on overlapping...such as in the picture...
![my http://notebook..](https://useruploads.socratic.org/oDFuwRelRwqxHi2Q2rkT_IMG_20171128_104144_891%5B1%5D.JPG)
#" "#(S-S) OVERLAPPING

![my http://notebook..](https://useruploads.socratic.org/bOPKClh1Qr6xCcbxNxwW_IMG_20171128_104159_614%5B1%5D.JPG)

#" "#(S-P) OVERLAPPING

![my http://notebook...](https://useruploads.socratic.org/qzqCeNkkT2O5pQazRbXm_IMG_20171128_104123_430%5B1%5D.JPG)

#" "#(P-P) OVERLAPPING

These three types of structure are mainly involved in producing #color(red)(sigma)"bonds"#....which emans single bonds...

But some time we see that there is #C-=C # bonds or, #C=C# bonds...
#" "#Here in the first case ,there is one #sigma# bond but the other bond is the# pi# bond who contains loose electrons but strengthens the whole bond formation...
#" "#In the #2nd# case there is two #pi #bonds... which produces by following type of overlapping(#color(red)("(side-wise overlapping)"#...

my notebook
#" "# (P-P) SIDE-WISE OVERLAPPING

Hope it helps...
Thank you...