A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #36 # and the height of the cylinder is #8 #. If the volume of the solid is #48 pi#, what is the area of the base of the cylinder?

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Answer 1 · 2017-01-08T22:15:47

#Area_(base)=12/5pi#

You know that:

#Volume_(solid)=Volume_(co)+Volume_(cy)#

and that

#Volume_(co)=1/3Area_(base)*36#

#Volume_(cy)=Area_(base)*8#

Then

#1/cancel3Area_(base)*cancel36^12+Area_(base)*8=48pi#

that's

#20Area_(base)=48pi#

#Area_(base)=cancel48^12/cancel20^5pi#

#Area_(base)=12/5pi#