A solid disk with a radius of 4 m and mass of 6 kg is rotating on a frictionless surface. If 960 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 12 Hz?
1 Answer
Feb 9, 2017
Explanation:
We are told we have a rotating spinning coin.
http://www.mariowiki.com/coin
Step 1. Gather the information that you know and need
- Mass of disk:
"mass"=m=6" kg" - Radius of disk:
"radius"=r=4" m" - Power applied to increase rotation:
P=960" W" - Frequency:
f=12" Hz" - Torque required: ??
Step 2. Determine the formula using the above givens
P is the power applied,P=tau omega - Therefore, torque is
tau=P"/"omega - Angular speed,
omega=f*2pi=12*2pi=24pi
Step 3. Plug your knows into the formula for torque