Question

A solution contains 0.063 g of oxalic acid, `H_2C_2O_4 * 2H_2O`, in 250 mL. What is the molarity of this solution?

Answer 1

`"Molarity"` `~=` `2xx10^-3*mol*L^-1`

Explanation:

`"Molarity"` `=` `"Moles of solute"/"Volume of solution"`

`=` `(0.063*g)/(126.07*g*mol^-1)xx1/(0.250*L)` `=` `??*mol*L^-1`