Question

A solution is made by dissolving 14.57g of sodium bromide in 415g of water. What is the molality of the solution?

Answer 1

`"Molality"="Moles of solute"/"Kilograms of solvent"`

Explanation:

For your problem,

`"Molality"=(14.57*g)/(102.89*g*mol^-1)xx1/(0.415*kg)` `~=` `0.342*mol*kg^-1`.

Would the `"molarity"` of the solution be different?