A spring with a constant of $12$ $kgs^-2$ is lying on the ground with one end attached to a wall. An object with a mass of $5$ $kg$ and speed of $3$ $ms^-1$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $12$ $kgs^-2$ is lying on the ground with one end attached to a wall. An object with a mass of $5$ $kg$ and speed of $3$ $ms^-1$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-02-22T22:26:16

The kinetic energy of the moving mass, $E_k=1/2mv^2=1/2*5*3^2=22.5$ $J$ , will be converted to spring potential energy, $E_p=1/2kx^2$ . Rearranging this yields a compression of $x=sqrt((2E_p)/k)=1.94$ $m$ .

Explanation:

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A spring with a constant of $12$ $kgs^-2$ is lying on the ground with one end attached to a wall. An object with a mass of $5$ $kg$ and speed of $3$ $ms^-1$ collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of 1212 kgs^-2kgs^-2 is lying on the ground with one end attached to a wall. An object with a mass of 55 kgkg and speed of 33 ms^-1ms^-1 collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $12$ $kgs^-2$ is lying on the ground with one end attached to a wall. An object with a mass of $5$ $kg$ and speed of $3$ $ms^-1$ collides with and compresses the spring until it stops moving. How much will the spring compress?