A spring with a constant of $2 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $8 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $2 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $8 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-02-12T17:54:58

$x=2 m$

Explanation:

$E_k=1/2*m*v^2 " Object's kinetic energy"$
$E_k=1/2*8*1^2$
$E_k=4J$
$"the kinetic energy of object turns the potential energy on spring"$
$E_p=1/2*k*Delta x^2" Potential energy on spring"$
$E_p=1/2*2*Delta x^2$
$E_p=Delta x^2$
$E_p" must be equal to " E_k$
$4=Delta x^2$
$x=sqrt 4$
$x=2 m$

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A spring with a constant of $2 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $8 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of 2 (kg)/s^22 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 8 kg8 kg and speed of 1 m/s1 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of $2 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $8 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?