A spring with a constant of $2 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $4 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

Question

1723 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-03T06:40:23

The spring will compress by $=1.4m$

Mass of the object is $m=4kg$

Speed of the object is $v=1ms^-1$

The kinetic energy of the object is

$KE=1/2mv^2=1/2*4*1^2=2J$

This energy will be stored in the spring

$E=1/2kx^2$

The spring constant is $k=2kgs^-2$

Let the compression of the spring be $=xm$

Therefore,

$2=1/2*2*x^2$

$x^2=(2*2)/2=2m^2$

The compression is

$x=sqrt2=1.4m$

A spring with a constant of 2 (kg)/s^22 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 4 kg4 kg and speed of 1 m/s1 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?