A spring with constant #2# #kgs^-2# is lying on the ground with one end attached to a wall. An object with a mass of #1/2# #kg# and speed of #3/5# #ms^-1# collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with constant #2# #kgs^-2# is lying on the ground with one end attached to a wall. An object with a mass of #1/2# #kg# and speed of #3/5# #ms^-1# collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-06-05T08:42:57

The kinetic energy of the moving mass, #E_k=1/2mv^2=1/2xx1/2xx(3/5)^2=0.09# #J#, will be converted into spring potential energy in the spring, #E_p=1/2kx^2#. Rearranging, #x=sqrt((2E_p)/k)=sqrt((2xx0.09)/2)=0.30# #m# = #30# #cm#.

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A spring with constant #2# #kgs^-2# is lying on the ground with one end attached to a wall. An object with a mass of #1/2# #kg# and speed of #3/5# #ms^-1# collides with and compresses the spring until it stops moving. How much will the spring compress?

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