A spring with a constant of $2 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $6 kg$ and speed of $5 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-04-16T13:59:01

The spring will compress by $=8.66m$

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The spring constant is $k=2kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*6*(5)^2=75J$

This kinetic energy will be stored in the spring as potential energy.

$PE=75J$

So,

$1/2kx^2=75$

$x^2=150/2=75m^2$

$x=sqrt(75)=8.66m$

A spring with a constant of 2 (kg)/s^22 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 6 kg6 kg and speed of 5 m/s5 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?