Question

A spring with a constant of `3 (kg)/(s^2)` is lying on the ground with one end attached to a wall. An object with a mass of `5 kg` and speed of `7 m/s` collides with and compresses the spring until it stops moving. How much will the spring compress?

Answer 1

`Delta x=7 . sqrt(5/3) m`

Explanation:

`"energy on object is :" E_k=1/2.m. v^2`
`E_k= 1/2 . 5 .7^2`
`E_k=1/2 . 5. 49`
`"energy on spring :"E_p=1/2 . k . Delta x^2`
`E_k=E_P`
`cancel(1/2) .5 .49=cancel(1/2) .3 .Delta x^2`
`Delta x^2=5.49/3`
`Delta x=7 . sqrt(5/3) m`