A spring with a constant of $3 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $3 kg$ and speed of $5 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-05-19T12:43:03

The spring will compress by $=5m$

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The spring constant is $k=3kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*3*(5)^2=75/2J$

This kinetic energy will be stored in the spring as potential energy.

$PE=75/2J$

So,

$1/2kx^2=75/2$

$x^2=2*(75/2)/(3)=25m^2$

$x=sqrt(25)=5m$

A spring with a constant of 3 (kg)/s^23 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 3 kg3 kg and speed of 5 m/s5 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?