A spring with a constant of $3 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $5 kg$ and speed of $8 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $3 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $5 kg$ and speed of $8 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-02-11T18:27:02

$Delta x=8 sqrt (5/3) " m"$

Explanation:

$E_k=1/2 m* v^2 " the kinetic energy of object"$
$E_p=1/2 * k*Delta x^2$
$E_p=E_k$
$cancel(1/2)* 3* Delta x^2=cancel(1/2) .5*8^2$
$Delta x^2=(64*5)/3$
$Delta x=8 sqrt (5/3) " m"$

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A spring with a constant of $3 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $5 kg$ and speed of $8 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of 3 (kg)/s^23 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 5 kg5 kg and speed of 8 m/s8 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of $3 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $5 kg$ and speed of $8 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?