A spring with a constant of $3 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $4 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-05-18T11:53:38

The compression is $=1.15m$

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The spring constant is $k=3kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*4*(1)^2=2J$

This kinetic energy will be stored in the spring as potential energy.

$PE=2J$

So,

$1/2kx^2=2$

$x^2=2*2/(3)=1.33m^2$

$x=sqrt(1.33)=1.15m$

A spring with a constant of 3 (kg)/s^23 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 4 kg4 kg and speed of 1 m/s1 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?