A spring with a constant of $4 (kg)/(s^2)$ is lying on the ground with one end attached to a wall. An object with a mass of $4 kg$ and speed of $8 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-06-19T19:02:31

It will compress $8m$ .

Mass of object =4 kg
Velocity=8m/s

$KE=1/2 mv^2$
$KE=128 j$

Since ,energy is always conserved.

Spring potential energy = kinetic energy of that body

$PE= 1/2 K X^2$
$128=2 × X^2$
$64 = x^2$

$X= 8 m$

A spring with a constant of 4 (kg)/(s^2)4 (kg)/(s^2) is lying on the ground with one end attached to a wall. An object with a mass of 4 kg 4 kg and speed of 8 m/s 8 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?