A spring with a constant of $4 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $5 kg$ and speed of $5 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-06-20T18:08:59

The compression is $=5.59m$

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The spring constant is $k=4kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

The mass is $m=5kg$

The speed is $u=5ms^-1$

$KE=1/2*5*(5)^2=62.5J$

This kinetic energy will be stored in the spring as potential energy.

$PE=62.5J$

So,

$1/2kx^2=62.5$

$x^2=(2*62.5)/(4)=31.25m^2$

$x=sqrt(31.25)=5.59m$

A spring with a constant of 4 (kg)/s^24 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 5 kg5 kg and speed of 5 m/s5 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?