A spring with a constant of $4 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $4 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-02-02T22:14:07

I got $0.7m$

Explanation:

In theory all the Kinetic Energy of the object will be converted into Elastic Potential Energy so we can write:
$1/2mv^2=1/2kx^2$
$cancel(1/2)mv^2=cancel(1/2)kx^2$
rearranging and solving for the compression of the spring $x$ :
$x=vsqrt(m/k)=1*sqrt(2/4)=sqrt(1/2)=0.7m$

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A spring with a constant of $4 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of 4 (kg)/s^24 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 2 kg2 kg and speed of 1 m/s1 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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A spring with a constant of $4 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 kg$ and speed of $1 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?