A spring with a constant of 5 (kg)/(s^2) is lying on the ground with one end attached to a wall. An object with a mass of 5 kg and speed of 7 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer
May 22, 2017

The distance is =7m

Explanation:

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The spring constant is k=5kgs^-2

The kinetic energy of the object is

KE=1/2m u^2

KE=1/2*5*(7)^2=122.5J

This kinetic energy will be stored in the spring as potential energy.

PE=122.5J

So,

1/2kx^2=122.5

x^2=2*(122.5)/(5)=49m^2

x=sqrt(49)=7m