A spring with a constant of $5 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $6 kg$ and speed of $12 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

Question

2149 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-22T15:41:04

12m

Initially;

Kinetic energy of the mass : $1/2mv^2 = 1/2 *6*12^2 J$

Finally:

Kinetic energy of the mass : 0

Potential energy : $1/2kx^2 = 1/2 *(5 (kg)/s^2) x^2$

equating, we get :

$1/2 *6*12^2 J= 1/2 *(5 (kg)/s^2) x^2 => x~~12m$

*I would be so happy if $k$ and $m$ were the same.

A spring with a constant of 5 (kg)/s^25 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 6 kg6 kg and speed of 12 m/s12 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?