A spring with a constant of $6 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $3 kg$ and speed of $7 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-05-09T11:28:10

The compression is $=4.95m$

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The spring constant is $k=6kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*3*(7)^2=73.5J$

This kinetic energy will be stored in the spring as potential energy.

$PE=73.5J$

So,

$1/2kx^2=73.5$

$x^2=73.5*2/(6)=24.5m^2$

$x=sqrt(24.5)=4.95m$

A spring with a constant of 6 (kg)/s^26 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 3 kg3 kg and speed of 7 m/s7 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?