A spring with a constant of $6 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $9 kg$ and speed of $2 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-04-23T07:23:55

The spring will compress by $=2.45m$

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The spring constant is $k=6kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*9*(2)^2=18J$

This kinetic energy will be stored in the spring as potential energy.

$PE=18J$

So,

$1/2kx^2=18$

$x^2=36/6=6m^2$

$x=sqrt(6)=2.45m$

A spring with a constant of 6 (kg)/s^26 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 9 kg9 kg and speed of 2 m/s2 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?