A spring with a constant of $7 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $8 kg$ and speed of $4 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-05-08T10:18:52

The compression is $=4.28m$

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The spring constant is $k=7kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*8*(4)^2=64J$

This kinetic energy will be stored in the spring as potential energy.

$PE=64J$

So,

$1/2kx^2=64$

$x^2=64*2/(7)=18.29m^2$

$x=sqrt(18.29)=4.28m$

A spring with a constant of 7 (kg)/s^27 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 8 kg8 kg and speed of 4 m/s4 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?