A spring with a constant of $8 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 kg$ and speed of $3 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-05-04T12:46:01

The compression is $=1.5m$

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The spring constant is $k=8kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*2*(3)^2=9J$

This kinetic energy will be stored in the spring as potential energy.

$PE=9J$

So,

$1/2kx^2=9$

$x^2=9*2/(8)=2.25m^2$

$x=sqrt(2.25)=1.5m$

A spring with a constant of 8 (kg)/s^28 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 2 kg2 kg and speed of 3 m/s3 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?