A spring with a constant of $9 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $1 kg$ and speed of $3 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2017-06-01T05:55:36

The compression is $=1m$

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The spring constant is $k=9kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

$KE=1/2*1*(3)^2=4.5J$

This kinetic energy will be stored in the spring as potential energy.

$PE=4.5J$

So,

$1/2kx^2=4.5$

$x^2=2*(4.5)/(9)=1m^2$

$x=sqrt(1)=1m$

A spring with a constant of 9 (kg)/s^29 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 1 kg1 kg and speed of 3 m/s3 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?