A spring with a constant of $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 k g$ $2 kg$ and speed of $3 \frac{m}{s}$ $3 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-05-20T06:00:59

It compresses by $\sqrt{2}$ $sqrt2$ $m$ $m$

$\frac{1}{2} k x^{2} = \frac{1}{2} m v^{2}$ $1/2 kx^2 = 1/2 mv^2$

$k x^{2} = m v^{2}$ $kx^2 = mv^2$

$9 \cdot x^{2} = 2 \cdot 3^{2}$ $9 * x^2 = 2*3^2$

$x^{2} = 2 \Rightarrow x = \sqrt{2} m$ $x^2 = 2 =>x =sqrt2 m$

A spring with a constant of 9kgs29 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 2kg2 kg and speed of 3ms3 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?