A spring with a constant of $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 k g$ $2 kg$ and speed of $7 \frac{m}{s}$ $7 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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A spring with a constant of $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 k g$ $2 kg$ and speed of $7 \frac{m}{s}$ $7 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2016-03-04T14:06:50

$Delta x=7/3sqrt2" " m$

Explanation:

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$E_k=1/2*m*v^2" The Kinetic Energy of Object"$
$E_p=1/2*k*Delta x^2$
$"The Potential Energy of Spring Compressed"$
$E_k=E_p" Conservation of Energy"$
$cancel(1/2)*m*v^2=cancel(1/2)*k*Delta x^2$
$m*v^2=k*Delta x^2$
$2*7^2=9*Delta x^2$
$Delta x=sqrt(2*7^2/9)$
$Delta x=7/3sqrt2" " m$

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A spring with a constant of $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 k g$ $2 kg$ and speed of $7 \frac{m}{s}$ $7 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

1 Answer

Explanation:

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1 Answer

Explanation:

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A spring with a constant of $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 k g$ $2 kg$ and speed of $7 \frac{m}{s}$ $7 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?