A student adds 5.00 g of dry ice (solid CO_2CO2) to an empty balloon. What will be the volume of the balloon at STP after all the dry ice sublimes (converts to gaseous CO_2CO2)?

1 Answer
Dr. Hayek
May 5, 2016

V=2.56LV=2.56L

Explanation:

Assuming that the CO_2CO2 gas is behaving ideally, therefore, we can use the ideal gas law to find the volume occupied by the gas in a ballon by:

PV=nRT=>V=(nRT)/PPV=nRT⇒V=nRTP

At STP, the pressure is P=1atmP=1atm and the temperature is T=273KT=273K.

To find the number of mole of CO_2CO2, we can use the given mass as:

n=m/(MM)n=mMM, where MM=44g/(mol)MM=44gmol is the molar mass of CO_2CO2.

=>n=(5.00cancel(g))/(44cancel(g)/(mol))=0.114 mol

Therefore, the volume is:
=>V=(nRT)/P=(0.114cancel(mol)xx0.0821(L*cancel(atm))/(cancel(K)*cancel(mol))xx273cancel(K))/(1cancel(atm))=2.56L

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