A submarine descends below the ocean's surface at a of rate 75 feet per minute. How many feet below the ocean's surface will the submarine be in 12 minutes?

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Answer 1 · 2016-12-03T12:09:26

The submarine would be 900 below the ocean surface after 12 minutes assuming it started its descent at the surface of the ocean.

The formula for distance traveled (in this case the distance a submarine descends) over a period of time is:

$d = r \cdot t$ $d = r*t$ where $d$ $d$ is the distance traveled (or descended), $r$ $r$ is the rate of travel and $t$ $t$ is the time.

In this problem we are told the rate, $r$ $r$ is 75 feet per minute. And, we are told the time, $t$ $t$ , to calculate for which is 12 minutes.

Substituting these into the formula and calculating gives:

$d = (75feet)/(min) * 12 min$

$d = (75feet)/(cancel(min)) * 12 cancel(min)$

$d = 75feet * 12$

$d = 900 feet$