A substance has an empirical formula of $CH_2$ and a molar mass of 56 grams per mole. What is the molecular formula for this compound?

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Answer 1 · 2017-01-03T06:25:43

The molecular formula is always a whole number multiple of the empirical formula, so.........

$("empirical formula")xxn="Molecular formula"$ ,

i.e. $(12.01+2xx1.00794)*g*mol^-1xxn=56*g*mol^-1$

$n=(56*g*mol^-1)/((12.01+2xx1.00794)*g*mol^-1)$

And clearly, $n=4$ .

So $"molecular formula"$ $=$ $(CH_2)_4$

$=C_4H_8$

The stuff is a butylene OR a three-membered or four-membered ring.