A syringe contains 2.60 mL of gas at 20.0°C. What is the volume of gas after the temperature is increased to 68.0°C?

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A syringe contains 2.60 mL of gas at 20.0°C. What is the volume of gas after the temperature is increased to 68.0°C?

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Answer 1 · 2017-04-24T17:41:10

$V_{2} ≅ 3 \cdot m L$ $V_2~=3*mL$

Explanation:

From old $Charles' Law$ $"Charles' Law"$ we know that $V \propto T$ $VpropT$ , or $V = k T$ $V=kT$ for a given amount of gas at constant pressure. If we solve for $k$ $k$ , then $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1=V_2/T_2$ , and $V_{2} = \frac{V_{1}}{T_{1}} \times T_{2}$ $V_2=V_1/T_1xxT_2$ .

Of course, we must use $absolute temperatures$ $"absolute temperatures"$ , $T_{1} = (20.0 + 273.15) \cdot K$ $T_1=(20.0+273.15)*K$ , and $T_{2} = (68.0 + 273.15) \cdot K$ $T_2=(68.0+273.15)*K$ . And thus.......

$V_{2} = \frac{2.60 \cdot m L}{(20.0 + 273.15) \cdot K} \times (68.0 + 273.15) \cdot K = 3.03 \cdot m L$ $V_2=(2.60*mL)/((20.0+273.15)*K)xx(68.0+273.15)*K=3.03*mL$

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A syringe contains 2.60 mL of gas at 20.0°C. What is the volume of gas after the temperature is increased to 68.0°C?

1 Answer

Explanation:

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