A tank contains a mixture of helium, neon, and argon gases. lf the total pressure in the tank is 490. mmHg and the partial pressures of helium and argon are 21.5 mmHg and 10.2 mmHg, respectively, what is the partial pressure of neon?

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Answer 1 · 2018-06-23T15:11:56

Well the sum of the individual partial pressures is equal to the total pressure....

And so...

$P_{Total} = P_{He} + P_{Ne} + P_{Ar} = 490 \cdot m m \cdot H g$ $P_"Total"=P_"He"+P_"Ne"+P_"Ar"=490*mm*Hg$

But we are given that $P_{He} = 21.5 \cdot m m \cdot H g$ $P_"He"=21.5*mm*Hg$ , and that $P_{Ar} = 10.2 \cdot m m \cdot H g$ $P_"Ar"=10.2*mm*Hg$ ..

And so... $P_{Ne} = {490 - 21.5 - 10.2} \cdot m m \cdot H g} = 458.3 \cdot m m \cdot H g$ $P_"Ne"={490-21.5-10.2}*mm*Hg}=458.3*mm*Hg$ ..