A towns population went from 25,800 to 42,600 in 15 years. What was the percent of the change?

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A towns population went from 25,800 to 42,600 in 15 years. What was the percent of the change?

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Answer 1 · 2016-12-05T16:17:02

The percent change was 65.1% rounded to the nearest tenth.

Explanation:

The formula for percent change over a time period is:

$p = \frac{N - O}{O} \cdot 100$ $p = (N - O)/O * 100$ where $p$ $p$ is the percent change, $N$ $N$ is the new value and $O$ $O$ is the old value. In this case we are given the Old Value (25,800) and the New Value (42,600) so we can substitute these into the formula to calculate $p$ $p$ , the percent change:

$p = \frac{42600 - 25800}{25800} \cdot 100$ $p = (42600 - 25800)/25800 * 100$

$p = \frac{16800}{25800} \cdot 100$ $p = 16800/25800 * 100$

$p = \frac{1680000}{25800}$ $p = 1680000/25800$

$p = 65.1$ $p = 65.1$ rounded to the nearest tenth.

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A towns population went from 25,800 to 42,600 in 15 years. What was the percent of the change?

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