A train accelerates from rest at a constant rate #alpha# for distance X and time T(a).after that it retards at a constant rate #beta# for distance Y and time T(b).Which of the following relations is correct?
#(1) X//Y=alpha//beta=T(a)//T(b)#
#(2X//Y=beta//alpha=T(a)//T(b)#
#(3)X//Y=alpha//beta=T(b)//T(a)#
#(4)X//Y=beta//alpha=T(B)//T(a)#
1 Answer
Explanation:
Simply applying the law of kinematics for constant acceleration and retardation,to find the relationship.
For the
Now,at the end of first
So,putting the value of
or,
So,for the rest half of the journey,we can say,
And,
So,
And,
So,we can conclude,