A transverse wave is described by equation # y=y_0sin2pi(ft-x/lambda)#....The maximum velocity of particle will be 4times of velocity of wave provided...If #lamda# equals to?

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Answer 1 · 2017-06-02T05:59:21

A transverse wave is described by equation

# y=y_0sin2pi(ft-x/lambda)#

The maximum velocity of particle will be

#v_"max"="amplitude"xx2pif=y_0xx2pif #

Velocity of wave #v_"wave"=lamdaxxf#

By the condition of the problem

#v_"max"=4xx v_"wave"#

#=>y_0xx2pif=4xx lamdaxxf#

#=>lambda=(piy_0)/2#