A triangle has corners at #(2, 7 )#, ( 5, -2)#, and #( 1, -1)#. If the triangle is reflected across the x-axis, what will its new centroid be?

Question

What equation results when the function #f(x) = 3^(x)# is reflected in the x-axis and translated...
A triangle has corners at #(7, 1 )#, ( 3 , 2)#, and #( 8 , 5 )#. What will the new...
A triangle has corners at #(2, 1 )#, ( -4 , 3)#, and #( 8 , 5 )#. What will the new...
A triangle has corners at #(2, 1 )#, ( -4 , 3)#, and #( 1 , -2)#. What will the new...
A triangle has corners at #(2, 1 )#, ( 6 , 1)#, and #( 1 , -2)#. What will the new...
A triangle has corners at #(2, -5 )#, ( 6 , 1)#, and #( 1 , -2)#. What will the new...
A triangle has corners at #(2, -5 )#, ( 6 , 1)#, and #( 4 , 3)#. What will the new...
A triangle has corners at #(3, -5 )#, ( 2 , -1)#, and #( 4 , 3)#. What will the new...
A triangle has corners at #(2, -7 )#, ( 1 , -3)#, and #( 4 , 3)#. What will the new...
A triangle has corners at #(4, 6 )#, ( 1 , -3)#, and #( 1 , -4)#. What will the new...

1871 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-07T07:58:07

The new centroid #(8/3, -4/3)#

From the old centroid :(8/3, 4/3)

#x=(x_1+x_2+x_3)/3=(1+2+5)/3=8/3#
#y=(y_1+y_2+y_3)/3=(-1+7-2)/3=4/3#

Only the ordinate 4/3 will change to -4/3 located at the 4th quadrant.
So the new centroid is #(8/3, -4/3)#

God bless...I hope the explanation is useful.